Helper

E_charlie_d3_indep_V1

Section charlie_security_independence
Type Lemma
Proof Lines 4

Signature

Lemma E_charlie_d3_indep_V1 : P |= E_charlie_d3 _|_ V1.

Description

E_charlie_d3 is independent of V1 because D3 is independent of V1

Uses (0)

This lemma does not use any other lemmas from the stats.

Used By (0)

No lemmas in the stats use this lemma.

Coq Source Code

View on GitHub
Loading source code...
← Back to Stats